(x-1)(x+2)-x^2=5

Solution for (x-1)(x+2)-x^2=5 equation:

Simplifying
(x + -1)(x + 2) + -1x2 = 5

Reorder the terms:
(-1 + x)(x + 2) + -1x2 = 5

Reorder the terms:
(-1 + x)(2 + x) + -1x2 = 5

Multiply (-1 + x) * (2 + x)
(-1(2 + x) + x(2 + x)) + -1x2 = 5
((2 * -1 + x * -1) + x(2 + x)) + -1x2 = 5
((-2 + -1x) + x(2 + x)) + -1x2 = 5
(-2 + -1x + (2 * x + x * x)) + -1x2 = 5
(-2 + -1x + (2x + x2)) + -1x2 = 5

Combine like terms: -1x + 2x = 1x
(-2 + 1x + x2) + -1x2 = 5

Combine like terms: x2 + -1x2 = 0
-2 + 1x + 0 = 5
-2 + 1x = 5

Solving
-2 + 1x = 5

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 1x = 5 + 2

Combine like terms: -2 + 2 = 0
0 + 1x = 5 + 2
1x = 5 + 2

Combine like terms: 5 + 2 = 7
1x = 7

Divide each side by '1'.
x = 7

Simplifying
x = 7